Three coins are tossed. $P(\text{exactly two heads}) = $?
A$\dfrac{3}{8}$
B$\dfrac{1}{2}$
C$\dfrac{1}{8}$
D$\dfrac{1}{4}$
Answer & Solution
Correct answer: A. $\dfrac{3}{8}$
Sample space has 8 outcomes. Two-heads outcomes: HHT, HTH, THH (3 outcomes). $P = 3/8$.
Related questions
Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE For [[1,2],[2,4]], the determinant equals:If A is invertible, |A^{−1}| equals:For a 3 × 3 non-singular A with |A| = 5, the value of |adj A| is:For a non-singular square matrix A of order n, |adj A| equals:For non-singular A, B of the same order, (AB)^{−1} equals:For a non-singular A, (A^{−1})^{−1} equals: