Rolling a die: events A = 'even' and B = '$\le 3$'. $P(A \cup B) = $?
A$\dfrac{1}{3}$
B$\dfrac{5}{6}$
C$\dfrac{1}{2}$
D$\dfrac{2}{3}$
Answer & Solution
Correct answer: B. $\dfrac{5}{6}$
$A = \{2,4,6\}$, $B = \{1,2,3\}$, $A \cap B = \{2\}$. $P(A \cup B) = \frac{3}{6} + \frac{3}{6} - \frac{1}{6} = \frac{5}{6}$.
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