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Burning 0.963 g of benzene raises a bomb calorimeter by 8.39 degrees C. With a bomb capacity of 784 J/degree C and 925 mL of water, how much heat is produced?
AAbout 32.5 kJ
BAbout 6.6 kJ
CAbout 45.6 kJ
DAbout 39.0 kJ
Answer & Solution
Correct answer: D. About 39.0 kJ
1. Heat from the reaction is absorbed by both the water and the steel bomb.
2. Water density is 1.0 g/mL, so 925 mL of water has a mass of 925 g.
3. Heat taken by the water is 4.184 times 925 times 8.39, which is 32,471 J.
4. Heat taken by the bomb is 784 J per degree Celsius times 8.39, which is 6578 J.
5. Adding gives 39,049 J absorbed in total.
6. The reaction released that amount, so about 39.0 kJ of heat was produced.
7. Counting only the water gives 32.5 kJ, which is the trap of forgetting the bomb capacity.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 5 "Thermochemistry", section 5.2 Calorimetry_
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