A jet car moving in a straight line has a position of 525 m at 0.50 s and 2000 m at 6.40 s, and the position against time graph is a straight line. What is its average velocity?
A250 m/s
B145 m/s
C313 m/s
D395 m/s
Answer & Solution
Correct answer: A. 250 m/s
1. The graph is a straight line, so its slope is the average velocity and any two points may be used.
2. The rise is the change in position: 2000 m - 525 m = 1475 m.
3. The run is the change in time: 6.40 s - 0.50 s = 5.90 s.
4. Substitute the values: (1475 m) / (5.90 s) = 250 m/s.
5. Dividing 2000 m by 6.40 s alone gives 313 m/s and ignores the starting point.
_Source: OpenStax College Physics (CC BY 4.0), Ch 2 "Kinematics", section 2.8 Graphical Analysis of One-Dimensional Motion_
Related questions
Measuring time at all depends on the fact that:An airplane passenger moving 4 metres toward the rear of the plane has a displacement recoA cyclist rides 3 km west then turns and rides 2 km east. The magnitude of the displacemenA scalar such as temperature can be negative, and there the minus sign indicates:An object with negative acceleration whose acceleration points the same way as its motion Deceleration is best defined as acceleration that is:An acceleration of 8.33 metres per second squared due west means the velocity changes by:The SI unit of acceleration is metres per second per second because acceleration is: