The sum of deviations of observations from their **mean** $\bar{x}$ is always:
Anegative
Bzero
Cpositive
Dequal to $n$
Answer & Solution
Correct answer: B. zero
$\sum (x_i - \bar{x}) = \sum x_i - n\bar{x} = n\bar{x} - n\bar{x} = 0$.
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