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Kirchhoff's Current Law states that at any junction in an electric circuit, the total current entering the junction is equal to the total current leaving it. For the junction shown in the figure, which equation correctly represents this law? ![](https://qallery.app/diagrams/v2_7771aec9ec38/img-000.jpeg)

A$I_1+I_2+I_3=I_4+I_5+I_6$
B$I_4+I_5+I_6=I_1+I_2$
C$I_1+I_4=I_2+I_3+I_5+I_6$
D$I_1+I_2+I_3+I_4+I_5+I_6=0$
Answer & Solution
Correct answer: A. $I_1+I_2+I_3=I_4+I_5+I_6$
In the figure, $I_1$, $I_2$, and $I_3$ are directed toward the junction, while $I_4$, $I_5$, and $I_6$ are directed away from it. So by Kirchhoff's Current Law, the sum entering equals the sum leaving: $I_1+I_2+I_3=I_4+I_5+I_6$. ![](https://qallery.app/diagrams/v2_7771aec9ec38/img-000.jpeg)
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