For the cubic polynomial $p(x)=2x^3-5x^2-14x+8$, what is the sum of the products of its zeroes taken two at a time?

For a cubic polynomial $ax^3+bx^2+cx+d$, if the zeroes are $\alpha,\beta,\gamma$, then $\alpha\beta+\beta\gamma+\gamma\alpha=\dfrac{c}{a}$. Here $a=2$ and $c=-14$, so the value is $\dfrac{-14}{2}=-7$.