The area of a triangle with vertices $(4, 4)$, $(3, -2)$, $(-3, 16)$ is:
A$27$
B$24$
C$13$
D$54$
Answer & Solution
Correct answer: A. $27$
Area = $\dfrac{1}{2}|4(-2-16) + 3(16-4) + (-3)(4-(-2))|$ = $\dfrac{1}{2}|-72 + 36 - 18|$ = $\dfrac{1}{2}(54)$ = $27$.
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