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Using the factor tree shown, what is the prime factorisation of 32760? 
A$2^3\times 3^2\times 5\times 7\times 13$
B$2^2\times 3^3\times 5\times 7\times 13$
C$2^3\times 3\times 5^2\times 7\times 13$
D$2^3\times 3^2\times 5\times 11\times 13$
Answer & Solution
Correct answer: A. $2^3\times 3^2\times 5\times 7\times 13$
From the factor tree, the prime leaves are $2,2,2,3,3,5,7,13$. Grouping equal primes gives $32760=2^3\times 3^2\times 5\times 7\times 13$.
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