How many 5-digit positive integers can be formed using the digits 1, 2, 3, 4, 5, 6, 7 if no digit can occur more than once?
A$1680$
B$5040$
C$720$
D$2520$
Answer & Solution
Correct answer: D. $2520$
$7 \times 6 \times 5 \times 4 \times 3 = 2520 = {}^{7}P_{5}$.
Related questions
Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE For [[1,2],[2,4]], the determinant equals:If A is invertible, |A^{−1}| equals:For a 3 × 3 non-singular A with |A| = 5, the value of |adj A| is:For a non-singular square matrix A of order n, |adj A| equals:For non-singular A, B of the same order, (AB)^{−1} equals:For a non-singular A, (A^{−1})^{−1} equals: