Practice free →
HomeCBSE Class 9mathematicsnumbersystems › In long division for 1/7, the possible non-zero …

In long division for 1/7, the possible non-zero remainders are 1, 2, 3, 4, 5, 6 (six values). The decimal of 1/7 therefore:

AMust terminate within 6 steps
BMust either terminate or start repeating within at most 6 steps, because a remainder must eventually repeat
CContinues forever with random digits
DHas 7 digits before repeating
Answer & Solution
Correct answer: B. Must either terminate or start repeating within at most 6 steps, because a remainder must eventually repeat
At each step in long division by 7, only six non-zero remainders are possible. By the pigeonhole principle, within 7 steps a remainder must repeat — and once it does, the digit sequence loops. So 1/7 must terminate or repeat within at most 6 steps. In fact 1/7 = 0.142857142857… has a 6-digit repeating block — exactly matching the maximum possible cycle length.
Solve this in the app — CBSE Class 9 practice & 24k+ MCQs →
Related questions