Pascal's triangle row for index 5 reads:
A$1, 4, 6, 4, 1$
B$1, 10, 10, 1$
C$1, 5, 5, 1$
D$1, 5, 10, 10, 5, 1$
Answer & Solution
Correct answer: D. $1, 5, 10, 10, 5, 1$
Row 5: $\binom{5}{0}$ through $\binom{5}{5} = 1, 5, 10, 10, 5, 1$.
Related questions
Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE Penalty for wrong answers : THERE WILL BE PENALTY FOR WRONG ANSWERS MARKED BY A CANDIDATE For [[1,2],[2,4]], the determinant equals:If A is invertible, |A^{−1}| equals:For a 3 × 3 non-singular A with |A| = 5, the value of |adj A| is:For a non-singular square matrix A of order n, |adj A| equals:For non-singular A, B of the same order, (AB)^{−1} equals:For a non-singular A, (A^{−1})^{−1} equals: