Find the roots of $x^{2} - 2x + 5 = 0$.
A$x = -1 \pm 2i$
B$x = 1 \pm i$
C$x = 2 \pm i$
D$x = 1 \pm 2i$
Answer & Solution
Correct answer: D. $x = 1 \pm 2i$
$x = \dfrac{2 \pm \sqrt{4 - 20}}{2} = \dfrac{2 \pm 4i}{2} = 1 \pm 2i$.
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