Find the roots of $x^{2} + x + 1 = 0$.
A$x = 1 \pm i$
B$x = \dfrac{1 \pm i\sqrt{3}}{2}$
C$x = \dfrac{-1 \pm i\sqrt{3}}{2}$
DNo solution
Answer & Solution
Correct answer: C. $x = \dfrac{-1 \pm i\sqrt{3}}{2}$
$x = \dfrac{-1 \pm \sqrt{1 - 4}}{2} = \dfrac{-1 \pm i\sqrt{3}}{2}$.
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