If $4x + i(3x - y) = 3 + i(-6)$ where $x, y$ are real, find $x$ and $y$.
A$x = \dfrac{3}{4},\, y = \dfrac{33}{4}$
B$x = 3,\, y = -6$
C$x = 4,\, y = 3$
D$x = \dfrac{3}{4},\, y = -6$
Answer & Solution
Correct answer: A. $x = \dfrac{3}{4},\, y = \dfrac{33}{4}$
Equate real & imaginary: $4x = 3 \Rightarrow x = 3/4$. $3x - y = -6 \Rightarrow y = 9/4 + 6 = 33/4$.
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