$\displaystyle\int_0^1 x^2(1-x)^3\, dx = ?$ (Beta function)
A$1/60$
B$1/12$
C$1/24$
D$1/720$
Answer & Solution
Correct answer: A. $1/60$
$B(m, n) = \int_0^1 x^{m-1}(1-x)^{n-1}dx = (m-1)!(n-1)!/(m+n-1)!$.
Here $m = 3$, $n = 4$: $B(3,4) = 2! \cdot 3! / 6! = 12/720 = 1/60$.
Keep practising Unit 6B: Definite Integration & Riemann Sums
Browse all Unit 6B: Definite Integration & Riemann Sums questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
∫ from 0 to π/2 sin x cos x dx =For ∫ dx / sqrt(a² - x²), let x = a sin θ. Result:∫ from 0 to 2 (x² - 2x) dx =Reduction formula example: ∫ sinⁿ x dx (for n ≥ 2) =∫ from 1 to e (1/x) dx =∫ x ln x dx (integration by parts: u = ln x, dv = x dx):∫ from 0 to ∞ e^(-x) dx =Area under y = x² from x = 0 to x = 2: