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The quadratic formula giving the roots of $ax^2+bx+c=0$ is
A$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$
B$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{a}$
C$x=\dfrac{b\pm\sqrt{b^2-4ac}}{2a}$
D$x=\dfrac{-b\pm\sqrt{4ac-b^2}}{2a}$
Answer & Solution
Correct answer: A. $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$
1. The roots are given by the quadratic formula.
2. $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$.
3. The denominator is $2a$ and the sign before b is negative.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch10 'Quadratic Equations', §10.3_
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