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If at a junction the currents entering are $2\,\text{A}$, $3\,\text{A}$, and $5\,\text{A}$, while two currents leaving are $4\,\text{A}$ and $x$, what is $x$ according to Kirchhoff's Current Law?
A$4\,\text{A}$
B$6\,\text{A}$
C$10\,\text{A}$
D$14\,\text{A}$
Answer & Solution
Correct answer: B. $6\,\text{A}$
By KCL, total entering current equals total leaving current. Entering current is $2+3+5=10\,\text{A}$. So $4+x=10$, giving $x=6\,\text{A}$.