Solve $5x - 3 \geq 3x - 5$ for real $x$.
A$x \geq 1$
B$x \leq -1$
C$x \geq -1$
D$x \leq 1$
Answer & Solution
Correct answer: C. $x \geq -1$
Subtract $3x$: $2x - 3 \geq -5$.
Add 3: $2x \geq -2$.
Divide by 2: $x \geq -1$.
Verify at $x = -1$: $-5 - 3 = -8$ vs $-3 - 5 = -8$. Equal ✓.
At $x = 0$: $-3 \geq -5$ ✓.
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