Solve $3x - 2 < 2x + 1$ for real $x$.
A$x < 3$
B$x > 3$
C$x < -3$
D$x \leq 3$
Answer & Solution
Correct answer: A. $x < 3$
Subtract $2x$: $x - 2 < 1$.
Add 2: $x < 3$.
In interval form: $(-\infty, 3)$.
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