Solve $3(2 - x) \geq 2(1 - x)$ for real $x$.
A$x \geq -4$
B$x \geq 4$
C$x \leq -4$
D$x \leq 4$
Answer & Solution
Correct answer: D. $x \leq 4$
Expand: $6 - 3x \geq 2 - 2x$.
Add $3x$: $6 \geq 2 + x$.
Subtract 2: $4 \geq x$, i.e., $x \leq 4$.
Verify at $x = 4$: $3(-2) = -6$ and $2(-3) = -6$. Equal ✓.
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