Solve $3x - 7 > 5x - 1$ for real $x$.
A$x > -3$
B$x > 3$
C$x < -3$
D$x < 3$
Answer & Solution
Correct answer: C. $x < -3$
Subtract $5x$: $-2x - 7 > -1$.
Add 7: $-2x > 6$.
Divide by $-2$ (flip): $x < -3$.
Verify at $x = -4$: $3(-4) - 7 = -19$, $5(-4) - 1 = -21$. $-19 > -21$ ✓.
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