Solve $7x + 3 < 5x + 9$ over the real numbers.
A$x < 3$
B$x > 3$
C$x < -3$
D$x \leq 3$
Answer & Solution
Correct answer: A. $x < 3$
$7x - 5x < 9 - 3 \Rightarrow 2x < 6 \Rightarrow x < 3$.
Verify with $x = 0$: $3 < 9$ ✓.
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