Solve $4x + 3 < 6x + 7$ over the real numbers.
A$x > -2$
B$x < -2$
C$x < 2$
D$x > 2$
Answer & Solution
Correct answer: A. $x > -2$
Subtract $6x$: $-2x + 3 < 7$.
Subtract 3: $-2x < 4$.
Divide by $-2$ (negative — **flip** the sign): $x > -2$.
Verify with $x = 0$: $3 < 7$ ✓. With $x = -3$: $-9 < -11$? No. ✓
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