Solve $5x - 3 < 3x + 1$ over the real numbers.
A$x < -2$
B$x < 2$
C$x > 2$
D$x \leq 2$
Answer & Solution
Correct answer: B. $x < 2$
Subtract $3x$: $2x - 3 < 1$.
Add 3: $2x < 4$.
Divide by 2 (positive — sign preserved): $x < 2$.
Verify with $x = 1$: $5 - 3 = 2$ and $3 + 1 = 4$, so $2 < 4$ ✓.
With $x = 3$: $12 < 10$? No. ✓ confirms $x < 2$.
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