Solve $30x < 200$ when $x$ is a natural number.
A$\{1, 2, 3, 4, 5, 6, 7\}$
B$\{0, 1, 2, 3, 4, 5, 6\}$
C$\{1, 2, 3, 4, 5, 6\}$
D$\{1, 2, 3, 4, 5\}$
Answer & Solution
Correct answer: C. $\{1, 2, 3, 4, 5, 6\}$
Divide both sides by 30: $x < \dfrac{200}{30} = \dfrac{20}{3} \approx 6.67$.
Natural numbers (starting from 1) satisfying $x < 6.67$: $\{1, 2, 3, 4, 5, 6\}$.
- **B** includes 0 — but the NCERT convention is $\mathbb{N} = \{1, 2, 3, \ldots\}$.
- **C** wrongly includes 7 (since $30 \cdot 7 = 210 > 200$).
- **D** omits 6.
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