alleryIf the prime factorisations of two numbers are $2^3\times 3^2\times 5$ and $2^2\times 3\times 5^2$, then their HCF is
A$2^2\times 3\times 5$
B$2^3\times 3^2\times 5^2$
C$2\times 3^2\times 5$
D$2^2\times 5^2$
Answer & Solution
Correct answer: A. $2^2\times 3\times 5$
The HCF is formed by taking the common prime factors with the smallest powers.
For 2, the smaller power is 2
for 3, it is 1; for 5, it is 1. So HCF $=2^2\times 3\times 5$.
Keep practising Number Systems
Browse all Number Systems questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
Which of the following is not a polynomial in the variable $x$?The zero of the linear polynomial $ax+b$ with $a\neq 0$ isFor the polynomial $p(x)=x^2-3x-4$, what is the value of $p(-1)$?Which statement is true for a polynomial of degree $n$?If $\alpha$ and $\beta$ are the zeroes of the quadratic polynomial $ax^2+bx+c$ with $a\neqThe zeroes of the quadratic polynomial $x^2+7x+10$ areA quadratic polynomial has sum of zeroes $-3$ and product of zeroes $2$. Which of the follIf $\alpha,\beta,\gamma$ are the zeroes of the cubic polynomial $ax^3+bx^2+cx+d$, then $\a