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Tangents at points A and B on a circle centred at O meet at an external point C. In the quadrilateral OACB, why is the quadrilateral cyclic?

AOpposite angles at A and B sum to 180 degrees as both are right angles
BThe diagonals bisect each other inside the quadrilateral
CAdjacent angles each measure exactly 90 degrees
DOpposite sides are equal in length
Answer & Solution
Correct answer: A. Opposite angles at A and B sum to 180 degrees as both are right angles
1. OA is a radius and CA is a tangent at A, so angle OAC = 90°. 2. Similarly OB is a radius and CB is a tangent at B, giving angle OBC = 90°. 3. The two opposite angles at A and B add to 90° + 90° = 180°. 4. A quadrilateral is cyclic if and only if a pair of opposite angles sum to 180°. 5. Hence OACB is cyclic by the opposite-angle criterion, not by side or diagonal properties. _Source: SCERT Kerala Std X Mathematics Part-2, Chapter 7 "Tangents" (pp 159-172, 2019 ed.)._
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