alleryExpress $40^{\circ} 20'$ in degrees as a fraction.
A$\dfrac{121}{3}^{\circ}$
B$40.2^{\circ}$
C$40\dfrac{1}{2}^{\circ}$
D$42^{\circ}$
Answer & Solution
Correct answer: A. $\dfrac{121}{3}^{\circ}$
$20' = \dfrac{20}{60}^{\circ} = \dfrac{1}{3}^{\circ}$.
**So $40^{\circ} 20' = 40 + \dfrac{1}{3} = \dfrac{121}{3}^{\circ}$.**
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