A central angle of $60^{\circ}$ intercepts an arc of length $37.4$ cm in a circle. Find the radius. (Use $\pi = 22/7$.)

**Convert:** $60^{\circ} = \pi/3$ rad. Then $r = l/\theta = 37.4 / (\pi/3) = 37.4 \cdot 3 / \pi = 37.4 \cdot 3 \cdot 7 / 22 = 35.7$ cm.