If $A = \{x, y, z\}$ and $B = \{1, 2\}$, the number of relations from $A$ to $B$ is:
A$64$
B$32$
C$6$
D$128$
Answer & Solution
Correct answer: A. $64$
$n(A \times B) = 3 \cdot 2 = 6$. Number of relations = $2^{6} = 64$.
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