If $A = \{\text{red}, \text{blue}\}$ and $B = \{b, c, s\}$, how many ordered pairs are in $A \times B$?
A$2$
B$6$
C$5$
D$3$
Answer & Solution
Correct answer: B. $6$
$n(A \times B) = n(A) \cdot n(B) = 2 \cdot 3 = 6$.
The pairs: $(r, b), (r, c), (r, s), (bl, b), (bl, c), (bl, s)$.
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