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If $A=\begin{bmatrix}2&-3&-1\\4&2&3\end{bmatrix}$, then $A'$ is
A$\begin{bmatrix}2&-3&-1\\4&2&3\end{bmatrix}$
B$\begin{bmatrix}2&4\\-3&2\\-1&3\end{bmatrix}$
C$\begin{bmatrix}2&4&-3\\2&-1&3\end{bmatrix}$
D$\begin{bmatrix}2&-3\\-1&4\\2&3\end{bmatrix}$
Answer & Solution
Correct answer: B. $\begin{bmatrix}2&4\\-3&2\\-1&3\end{bmatrix}$
The transpose is obtained by interchanging rows and columns. So the first row $(2,-3,-1)$ becomes the first column and the second row $(4,2,3)$ becomes the second column, giving $\begin{bmatrix}2&4\\-3&2\\-1&3\end{bmatrix}$.
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