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**Markownikoff's rule** for addition of HX to an unsymmetrical alkene states:
AH attaches to the carbon with fewer hydrogens
BH attaches to the carbon with more hydrogens (i.e. X goes to the more-substituted carbon, forming the more stable carbocation)
CX always attaches to the terminal carbon
DAddition is purely random
Answer & Solution
Correct answer: B. H attaches to the carbon with more hydrogens (i.e. X goes to the more-substituted carbon, forming the more stable carbocation)
Markownikoff: in HX + asymmetric alkene, H adds to the C with more H atoms (the less-substituted C), and X to the more-substituted carbon. Explained by stability of the carbocation intermediate (3° > 2° > 1°).
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