In a circle of radius 7 cm, a tangent and a chord meet at the point of contact with an angle of 60 degrees. The length of the chord is
A7 (square root of 3) cm
B7 cm
C14 cm
D7/2 cm
Answer & Solution
Correct answer: A. 7 (square root of 3) cm
1. Tangent-chord angle 60 means central angle 2 × 60 = 120 degrees subtended by chord.
2. Chord squared = 2 r squared (1 - cos(120)) = 2 × 49 × 3/2 = 147.
3. Chord = square root of 147 = 7 (square root of 3) cm.
_Source: syllabus Mathematics, Ch 10 "Circles", §10.3_
Keep practising Triangles and Circles
Browse all Triangles and Circles questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
Two circles touch each other externally at P. A common tangent at P meets another common tIn a circle, two chords AB and CD intersect inside at P. If AP × PB = 8 and CP = 4, then PA point P is 25 cm away from the centre O of a circle and the tangent PT to the circle is Two parallel tangents are drawn to a circle of radius 8 cm. The distance between them isA tangent at point P of a circle of radius 5 cm is parallel to a chord 8 cm long. The distA circle touches all four sides of a quadrilateral ABCD with AB = 6, BC = 7, CD = 4. Then PA and PB are tangents from a point P to a circle. If angle APB = 90 degrees, the radius aA line drawn through the centre of a circle to bisect a chord is