A 100 kg object is uniformly accelerated from 5 ms⁻¹ to 17 ms⁻¹ in 6 s. The magnitude of the force applied on the object is _____.

1. Acceleration a = (v − u)/t = (17 − 5)/6 = 2 ms⁻². 2. Force F = ma = 100 × 2 = 200. 3. Force is measured in newtons, so F = 200 N. _Source: RRB Group D CEN-02/2018 PYQ, Q.16._