If sec^4(theta) - sec^2(theta) = 3, then the value of tan^4(theta) + tan^2(theta) is:

1. Let s = sec^2(theta) = 1 + tan^2(theta). Then s^2 - s = s(s - 1) = 3. 2. Here s - 1 = tan^2(theta), so s(s-1) = (1 + tan^2)(tan^2) = tan^2 + tan^4. 3. Thus tan^4(theta) + tan^2(theta) = 3. _Source: RRB Group D CEN-02/2018 PYQ, Q.57._