If the molecular weight of a compound is 60 and its empirical formula weight is 30, then the value of $n$ in $\text{Molecular formula} = n \times \text{empirical formula}$ is
A1
B2
C3
D30
Answer & Solution
Correct answer: B. 2
Here, $n=\dfrac{\text{molecular weight}}{\text{empirical formula weight}}=\dfrac{60}{30}=2$. So the molecular formula is twice the empirical formula.