If $f$ is an odd function, then $\displaystyle\int_{-a}^{a} f(x)\,dx$ equals
A$2\displaystyle\int_0^a f(x)\,dx$
B$\displaystyle\int_0^a f(x)\,dx$
C$0$
D$2f(a)$
Answer & Solution
Correct answer: C. $0$
1. For an odd function $f(-x)=-f(x)$.
2. By property $\mathbf{P_7}$(ii), the contributions over $[-a,0]$ and $[0,a]$ cancel.
3. Hence $\int_{-a}^{a} f(x)\,dx=0$.
4. Option A is the even-function case.
_Source: syllabus Mathematics Ch 7 "Integrals", p.343_
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