For the car with $x=t^2\left(2-\dfrac{t}{3}\right)$ reaching Q at $t=4…

Question

For the car with $x=t^2\left(2-\dfrac{t}{3}\right)$ reaching Q at $t=4$ s, the distance PQ is

Accepted Answer

C. $\dfrac{32}{3}$ m

1. The car reaches Q at $t=4$ s.
2. $x|_{t=4}=4^2\left(2-\dfrac{4}{3}\right)$.
3. $=16\left(\dfrac{6-4}{3}\right)=16\cdot\dfrac{2}{3}=\dfrac{32}{3}$.
_Source: NCERT Class 12 Mathematics Ch 6 "Application of Derivatives", p.30_

Answer

$\dfrac{16}{3}$ m

Answer

$\dfrac{64}{3}$ m

Answer

$16$ m