If $\mathbf{A}=\langle 1,2,3\rangle$, then $3\mathbf{A}$ equals
A$\langle 3,6,9\rangle$
B$\langle 1,6,9\rangle$
C$\langle 4,5,6\rangle$
D$\langle 3,2,1\rangle$
Answer & Solution
Correct answer: A. $\langle 3,6,9\rangle$
Scalar multiplication multiplies each component by the scalar. So $3\mathbf{A}=\langle 3\cdot 1,3\cdot 2,3\cdot 3\rangle=\langle 3,6,9\rangle$.
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