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If a point has coordinates $(x,y)$, then its position vector from the origin is ![](https://qallery.app/diagrams/v2_91ca62eb8d92/img-003.jpeg)

A$\vec r = x\hat{i} - y\hat{j}$
B$\vec r = y\hat{i} + x\hat{j}$
C$\vec r = x\hat{i} + y\hat{j}$
D$\vec r = \sqrt{x^2+y^2}\,(\hat{i}+\hat{j})$
Answer & Solution
Correct answer: C. $\vec r = x\hat{i} + y\hat{j}$
For a point $P(x,y)$, the notes give the position vector as $\vec r = x\hat{i} + y\hat{j}$. Its magnitude is $|\vec r| = \sqrt{x^2+y^2}$, not the vector form in option D.
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