If the angle between vectors $\vec A$ and $\vec B$ is $90^\circ$, then

Question

Accepted Answer

B. $\vec A\cdot\vec B = 0$

The dot product is $\vec A\cdot\vec B = AB\cos	heta$.
For $	heta=90^\circ$, $\cos 90^\circ=0$, so the dot product is zero.
In contrast, the cross-product magnitude is maximum at right angles and equals $AB$.

Answer

$\vec A\cdot\vec B = AB$

Answer

$|\vec A	imes\vec B| = 0$

Answer

$\vec A	imes\vec B$ is parallel to $\vec A$

If the angle between vectors $\vec A$ and $\vec B$ is $90^\circ$, then

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