Question 7: If the angle between vectors A and B is $\theta$, then the value of the product $(B\times A).A$ is equal to
ABA² cos θ
BBA² sin θ
Czero
DBA² sin θ cos θ
Answer & Solution
Correct answer: C. zero
B×A will be perpendicular to both A and B.
$$
(B \times A).A = (B \times A)A \cos \theta \text{ (here } \theta = 90^\circ\text{)}
$$
$$
= |B \times A| |A| \cos 90
$$
$$
= 0
$$
Hence option c is the answer.
Related questions
The angle θ between two PLANES with normals n1 and n2 satisfies:A point R divides the line joining P (position vector a) and Q (position vector b) INTERNAFor direction cosines l, m, n of any line in 3D:The Cartesian equation of a plane with intercepts 2, 3, 6 on the x, y, z axes is:The vector triple product a × (b × c) simplifies via:The scalar triple product [a b c] geometrically represents:A UNIT VECTOR in the direction of v = 3i + 4j is:Two non-zero vectors a and b are PERPENDICULAR if and only if: