A body of mass 2 kg starts from rest and reaches 6 m per second in 3 s. The applied force is:

1. Use v = u + at to find acceleration first. 2. Given u = 0, v = 6 m per second, t = 3 s, so a = (6 − 0) / 3 = 2 m per second squared. 3. Apply Newton's second law F = m·a. 4. F = 2 kg × 2 m per second squared = 4 N. 5. Option D wrongly multiplies mass by final velocity; A divides instead of multiplies. _Source: Selina Concise Physics ICSE Class 9, Ch 3 'Laws of Motion' (aplustopper.com extract)_