If a curve has slope $m$ at a point, then the slope of the normal at that point is
A$m$
B$\dfrac{1}{m}$
C$-m$
D$-\dfrac{1}{m}$
Answer & Solution
Correct answer: D. $-\dfrac{1}{m}$
The tangent and normal are perpendicular, so the product of their slopes is $-1$ when both are finite. Hence if tangent slope is $m$, normal slope is $-\dfrac{1}{m}$.
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