alleryStart learning →Two resistors of $10\Omega$ each are connected in PARALLEL. The total resistance is
A$20\Omega$
B$10\Omega$
C$2\Omega$
D$5\Omega$
Answer & Solution
Correct answer: D. $5\Omega$
1. PARALLEL of two resistors: $R_{total} = \dfrac{R_1 R_2}{R_1 + R_2}$.
2. For equal resistors: $R_{total} = R/n$ where $n$ is the number in parallel.
3. Here: $R_{total} = 10/2 = 5\Omega$.
4. Parallel resistance is ALWAYS LESS than any individual resistor.
5. Option A is the series result. Options B, C are wrong values.
_Source: Tony Kuphaldt, "Lessons in Electric Circuits — DC", Vol I, Ch 5 (Parallel resistors)._
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