alleryStart learning →Three resistors of $10\Omega$, $20\Omega$, $30\Omega$ are connected in SERIES. The total resistance is
A$5.45\Omega$
B$10\Omega$
C$60\Omega$
D$600\Omega$
Answer & Solution
Correct answer: C. $60\Omega$
1. SERIES: $R_{total} = R_1 + R_2 + R_3$.
2. $R_{total} = 10 + 20 + 30 = 60\Omega$.
3. Series resistance ALWAYS exceeds any individual resistor.
4. Option A is the parallel formula. Option B is just $R_1$. Option D multiplies instead of adds.
_Source: Tony Kuphaldt, "Lessons in Electric Circuits — DC", Vol I, Ch 5 (Series resistors)._
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