Home › GATE EE › electricalengineering › Electric Circuits › Three resistors of $10\Omega$, $20\Omega$, $30\O…
Three resistors of $10\Omega$, $20\Omega$, $30\Omega$ are connected in SERIES. The total resistance is
A$5.45\Omega$
B$10\Omega$
C$60\Omega$
D$600\Omega$
Answer & Solution
Correct answer: C. $60\Omega$
1. SERIES: $R_{total} = R_1 + R_2 + R_3$.
2. $R_{total} = 10 + 20 + 30 = 60\Omega$.
3. Series resistance ALWAYS exceeds any individual resistor.
4. Option A is the parallel formula. Option B is just $R_1$. Option D multiplies instead of adds.
_Source: Tony Kuphaldt, "Lessons in Electric Circuits — DC", Vol I, Ch 5 (Series resistors)._
Related questions
The QUALITY FACTOR Q of a series RLC resonant circuit measuresThe IMPEDANCE of a series RL circuit at angular frequency $\omega$ isAn RMS AC voltage of $230\,\text{V}$ drives a $100\Omega$ RESISTIVE load. The real power dIn an AC circuit with a pure CAPACITOR, the currentIn an AC circuit with a pure INDUCTOR, the currentA purely RESISTIVE AC load has voltage and current that arePOWER FACTOR is defined asThe resonant frequency of an LC circuit with $L = 100\,\text{mH}$ and $C = 1\,\mu\text{F}$