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The derivative of the natural logarithm function, d/dx [ln(x)] equals:
A$e^x$ (the exponential function)
B$\ln(x)$ (the function unchanged)
C$1/x$ (the reciprocal of x)
D$x \ln(x)$ (product unchanged)
Answer & Solution
Correct answer: C. $1/x$ (the reciprocal of x)
d/dx [ln x] = 1/x. Foundational derivative. From this: d/dx [log_a x] = 1/(x ln a). Domain: x > 0.
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