Two blocks of masses $4\, ext{kg}$ and $6\, ext{kg}$ are in contact …

Question

Two blocks of masses $4\,	ext{kg}$ and $6\,	ext{kg}$ are in contact on a frictionless horizontal surface. A horizontal force of $50\,	ext{N}$ is applied to the system. What is the acceleration of the two-block system?

Accepted Answer

C. $5\,	ext{m s}^{-2}$

Treat the two blocks as one system of total mass $4+6=10\,	ext{kg}$. Then $a = F/m = 50/10 = 5\,	ext{m s}^{-2}$. Hence option C is correct.

Answer

$2\,	ext{m s}^{-2}$

Answer

$3\,	ext{m s}^{-2}$

Answer

$10\,	ext{m s}^{-2}$

Two blocks of masses $4\,\text{kg}$ and $6\,\text{kg}$ are in contact on a frictionless horizontal surface. A horizontal force of $50\,\text{N}$ is applied to the system. What is the acceleration of the two-block system?